WebThe largest integer which can perfectly divide two integers is known as GCD or HCF of those two numbers. For example, the GCD of 4 and 10 is 2 since it is the largest integer that can divide both 4 and 10. Example: 1. Find HCF/GCD using for loop. #include using namespace std; int main() { int n1, n2, hcf; cout << "Enter two … WebOct 8, 2024 · Suppose we have four numbers a, b, c and d. We shall have to find maximum among them by making our own function. So we shall create one max() function that …
C program to find greatest among four input integers
WebTags for GCD - Greatest Common Divisor using Functions in C. sample hcf; sample gcd; greatest common divisor program using fucntions; find gcd in c; finding hcf; highest common factor; c program to find gcd of two numbers; c; c program for gcd using function; c program to find gcd of three numbers using function; c program to find gcd … WebIt computes max1 = max (a, b) and max2 = max (c, d), as well as min1 = min (a, b) and min2 = min (c, d), using the first 2 if s. Then the maximum is equal to max (max (a, b), max (c, d)) = max (max1, max2). (The 3rd if .) And the minimum is equal to min (min (a, b), min (c, d)) = min (min1, min2). (The 4th if .) highline news
c - Using only 4
WebNov 9, 2024 · C Program To Find Largest Of N Numbers Using While Loop #include int main(void) { int n; int max = 0; printf("Enter a number (0 to exit): "); scanf("%d", &n); while (n != 0) { if (max < n) { max = n; } printf("Enter a number (0 to exit): "); scanf("%d", &n); } printf("Max is: %d", max); } Output: WebJun 24, 2024 · The task is to write a program to find the largest number using ternary operator among: Two Numbers Three Numbers Four Numbers Examples : Input : 10, 20 Output : Largest number between two numbers (10, 20) is: 20 Input : 25 75 55 15 Output : Largest number among four numbers (25, 75, 55, 15) is: 75 A Ternary Operator has … Web#include using namespace std; int main() { double n1, n2, n3; cout > n1 >> n2 >> n3; // check if n1 is the largest number if(n1 >= n2 && n1 >= n3) cout = n1 && n2 >= n3) cout << "Largest number: " << n2; // if neither n1 nor n2 are the largest, n3 is the largest else cout << "Largest number: " << n3; return 0; } … highline nine gallery